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M8 shutter actuations


Clandrel

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Claus, go here:

 

http://www.l-camera-forum.com/leica-forum/leica-m8-forum/35415-determining-shutter-actuations-m8.html

 

You can find these by clicking on the Search button above.

 

Don't forget to convert from hexadecimal.

 

Thanks for the info, Bill. I just tried it with my M8 and found that the camera's counter is off by 174 frames. Must have happened when I used a new SD card without formatting first. Admittedly, 174 frames is nothing, but it's nice to know what the actual count really is.

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The actual actuation number of every actuation is embedded in the file and can be read in hexadecimal in the metadata (EXIF), in Bridge or ACDSee for instance.

It is labeled “Image Unique ID”, and reads something like 0000000000c5, 5r0, etc.

Only the last non-zero digits indicate the absolute number of the picture, expressed in hexadecimal.

There are tools on the web which can convert this number into its decimal equivalent.

 

But it is easy to decipher it yourself.

Hexadecimal means “base 16” (decimal is base 10).

Decimal requires 10 digits: 0, 1, 2, ….9

Hexadecimal requires 16 digits which are: 0, 1, 2, ….9, a, b, c, d, e, f

 

In decimal, each digit indicates how many powers of 10 it represents: “1980” indicates 1x1000 + 9x100 + 8x10 + 0

 

By the same token, in hexadecimal each digit or letter(a to f) indicates how many powers of 16 it represents.

 

For instance, the first capture with my M8 was 000000068, that is 6x16 + 8 = 96 + 8 = 104, meaning that 103 actuations took place during manufacturing.

If you are looking at a second-hand M8, you may read something like: 2cf4

This translates as 2x4096 + 12x256 + 15x16 + 4 = 8192 + 3072 + 240 + 4 = 11,508 actuations.

Another example: f001 = 15x4096 + 0x256 + 0x16 + 1= 60441 actuations. I wouldn’t buy it!

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