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135 mm on M8 vs M9


Anguish

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If one were to crop an M9 image made with a 135 mm lens to the equivalent of what's captured by the M8 sensor, how much finer would that cropped image be?

Potential answer: M9 18 MP x .7518 (crop factor) = 13.9 MP compared to the M8's 10 MP.

Would this equation yield a valid comparison? If so, how much of an advantage is the 3.9 MP?

Potential answer - almost a 40 percent advantage.

Is there a flaw in this analysis?

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Hans' computation is the correct one : in practice, cropping M9 image to 10 MP makes a pic virtually identical in definition to the one taken with M8 - same focal.

BUT... M9 has another sensor, a newer one, and can process 16 (14 indeed) bit per pixel files, so even if resolution in itself is in theory the same, it's probable that M9 cropped image is slightly better.

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Ang--

 

Crop factor has to do only with a comparison of frame diagonals, not with number of pixels.

 

Since M8 and M9 have the same 6.8 µm pixel pitch, there's no difference between them.

 

That is, since the two cameras have the same pixel density, if you put a 135 on an M9 and then crop the image to the same physical size as the M8's sensor, you'll get exactly the same number of pixels.

 

So any differences between the two would arise from the fact that the M9 has a later generation sensor with a thicker IR filter, and that the lens doesn't have a UV/IR-Cut filter as it would on the M8.

 

In other words, you're not likely to see any difference at all.

 

And remember, the question has the same answer with any focal length, not just 135.

 

 

EDIT: Damn! Luigi, you and Hans beat me again! :) I gotta quit opening so many threads at one time. :(

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