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M8 DNG file size


pmun

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16bit to 8bit???

Just a guess.

 

Why are you worried about it? Don't you like the M8 files? Bigger is not always better.

 

I use enough HD space already, especially if you process the DNG's into TIFF or PSD files. They get to around 59MB without any layers. Add in LR compatiblility if you use any layers and the file jumps to 160+MB.

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Thanks Shootist, I’m not worried, just curious. I assumed a larger sensor would create larger files. I’m new to the M8, but I’m happy with the files so far, much more detail than my GRD2, that’s another reason why I thought the files would be bigger.

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Because Leica has a very intelligent compression that works with pointers to LUT with logarithmic compression.

 

What does 'pointers to LUT with logarithmic compression' mean please?

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What does 'pointers to LUT with logarithmic compression' mean please?

 

It has been a long night, and Jaapv wasn't very clear. Each pixel value in the DNG file from an M8 is actually the square root of the raw data, stored as an 8-bit number, so 10 MPixels gives you 10 MBytes. That reduces the wasted bits in the highights and has little effect on the shadow information. There was a long debate on this, but there seems to be no or little image degradation in return for a 2x gain in processing speed and storage. There are no logarithms involved. The mapping from the original data to the saved data is contained in a look-up table (LUT) which is pasted into every DNG file. This is a standard trick that any DNG format file can use. There is an article by Michael Hussman, I think, in LFI about a year ago that explains the transformation and shows some pictures made before Leica decided to use this compression, to show why they concluded it didn't hurt to do so.

 

scott

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In other words, the Leica M8 DNGs are almost exactly the same size for each shot, namely the size of an 8-bit single-channel image (R or G or B for each pixel). 10MB = 10MP @ 1 byte per pixel.

 

The quality is much better than for normal 8-bit images, however, since the values are more evenly distributed throughout the brightness range, and not almost all in the bright areas.

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