DOUG66 Posted August 21, 2010 Share #21 Posted August 21, 2010 Advertisement (gone after registration) I do not have a source but as Pete has explained, the laser beam is now passing through the telescope and being magnified and the exit from the viewfinder is larger than the 1.25mm exit hole of the laser. I can however give you an example: the old 135mm Elmarit which has attached telescopic specs cat. no. 11829. The magnification of the specs is 1.5 which does two things it allowe the 90mm frame lines in the viewfinder to act as 135mm frame lines and it increases the effective base of the rangefinder to enable more accurate focusing. Focusing with a laser is exploiting the same principal. Doug. Link to post Share on other sites More sharing options...
Advertisement Posted August 21, 2010 Posted August 21, 2010 Hi DOUG66, Take a look here Focusing Issues. I'm sure you'll find what you were looking for!
Guest mc_k Posted August 22, 2010 Share #22 Posted August 22, 2010 It seems clear to me. In 'normal' usage light travels through the viewfinder and into your eye and is magnified (diminished) by a factor of 0.68 owing to the optics of the viewfinder. But when shining the laser through the viewfinder onto a subject the light is travelling in the opposite direction and the viewfinder's optics will magnify the laser by 1/0.68 = 1.47. ... this is clear, but wasn't my question. But I get it, the sensitivity has only to do with the scaling of the distance between the two images, whether seen through the viewfinder or projected by the laser. And the exit hole of the laser has no effect on the sensitivity of the setup, any more than the size of an ink dot you focus on affects the sensitivity. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 22, 2010 Share #23 Posted August 22, 2010 ... o.k., so you would need to add a better than 2X magnifier to compete with the laser in this aspect. How do you take advantage of this? Can you test focus at, say, distances of 12 ft. or more? What would you use for a target? What is the limiting factor at a distance: lens resolution, target, ability to focus? Link to post Share on other sites More sharing options...
DOUG66 Posted August 22, 2010 Share #24 Posted August 22, 2010 Hi McKeogh K, On some of the first tests that I carried out M.T. (private communication) pointed out to me that the sensor plane should be maintained at the 30 degrees to the chart and rotating the camera altered this angle and introduced an error. However the error is different depending on which side of the chart is furthest from the camera, as the camera is always rotated anti- clockwise. I described this wrongly as an apparent change in depth of focus, it is really a reduction in error. The micrometer stage is the better solution keeping the angle constant in the horizontal set-up. The vertical set-up is much easier. Your other point regarding testing at greater distances. I am working on this. The first step is the small laser alignment device which clips into the flash shoe. This is shown in the two photos I posted already in this thread. The idea is to align the laser beam exactly above the axis of the lens and use this to maintain the required 30 degree angle. I have been testing this device today. The first problem is adjusting the lateral alignment of the laser to bring it exactly over the lens axis. As you will appreciate the precision required in the making of this device is extremely high. I have discovered that it also requires an angular adjustment as the alignment of the flash shoe though good, for the distances required is not good enough. So it is back to the drawing board. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 22, 2010 Share #25 Posted August 22, 2010 ...with the RHS side of the chart furthest from the camera. This ison account of the paralax shift of the range finder of the Leica. This artificially reduces the aparant depth of focus of the lens. Sloping the chart the other way increases the depth of focus. This is due to the slight angular offset of the sensor plane as the camera is focussed on near objects... o.k. I get this but why not explicitly say it minimizes an error Link to post Share on other sites More sharing options...
Guest mc_k Posted August 22, 2010 Share #26 Posted August 22, 2010 sorry, didn't see your post! Thanks, I appreciate the info. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 23, 2010 Share #27 Posted August 23, 2010 Advertisement (gone after registration) apparently, if you try to shoot a ruler/chart at x degrees (to the lens axis) and you are off by +-y degrees, the percent error in your result is [1 - (cos x) / (cos (x+-y)] X 100 E.g. if you are off by 5 degrees your result will be off by 4-6 % (30 deg. target) or 8-10 % (45 deg. target) or 13-18 % (60 deg. target). So you can see that how you slope the target makes a little bit of a difference, and your angle makes even more of a difference. Link to post Share on other sites More sharing options...
farnz Posted August 23, 2010 Share #28 Posted August 23, 2010 apparently, if you try to shoot a ruler/chart at x degrees (to the lens axis) and you are off by +-y degrees, the percent error in your result is [1 - (cos x) / (cos (x+-y)] X 100 E.g. if you are off by 5 degrees your result will be off by 4-6 % (30 deg. target) or 8-10 % (45 deg. target) or 13-18 % (60 deg. target). So you can see that how you slope the target makes a little bit of a difference, and your angle makes even more of a difference. Should that be [1 - {(cos x) / (cos (x+-y)}] X 100? Pete. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 23, 2010 Share #29 Posted August 23, 2010 Should that be [1 - {(cos x) / (cos (x+-y)}] X 100? Pete. It's worse than that, I have an extra " ( ". It should be [1 - (cos x) / cos (x+-y)] X 100 (And you could also add your own absolute value sign around the whole thing.) In other words, if you shoot a ruler/chart at a "bad" angle, the bad result times the cosine of the bad angle = the true result times the cosine of the true angle. This you can get from a diagram with the two lens axes, the two targets sloped in the different directions, and the two critical focus planes. The takeaway for me is that if you are a little sloppy, there is an error just from setting up the target. Link to post Share on other sites More sharing options...
Nicoleica Posted August 23, 2010 Share #30 Posted August 23, 2010 OK. I think I understand the equation now. If you don't set it up perfectly, you'll absolutely get more errors 'cos of this and 'cos of that. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 24, 2010 Share #31 Posted August 24, 2010 OK. I think I understand the equation now. If you don't set it up perfectly, you'll absolutely get more errors 'cos of this and 'cos of that. o.k., a laser wit by all sines Link to post Share on other sites More sharing options...
Guest mc_k Posted August 24, 2010 Share #32 Posted August 24, 2010 I guess that covers errors from setting up the target and from focusing the target--how about from reading the target? Does anyone else use the moire? I've seen this mentioned in a couple of places. Link to post Share on other sites More sharing options...
DOUG66 Posted August 25, 2010 Share #33 Posted August 25, 2010 Hi, I think I might have come up with a method of setting up the test chart accurately which I will publish here when I get it checked out. I have been busy in the workshop making the components. One of the components requires a extremely accurate 30 deg angle.. I have just measured this component and find that the angle is 30.017 deg. an error of 0.06%. However when I put this figure into the formula it gives an error of 0.02%. Since errors are additive , how can an error in a component result in a smaller total error in the overall test. Am I missing something ? Doug. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 26, 2010 Share #34 Posted August 26, 2010 If you're cutting out paper right triangles, and making a mess of one of the other angles, if we use your numbers (30 vs. 30. 017 degrees) the percent error in the hypotenuse is less than the percent error in the angle. If I've made a mistake, it should be easy enough for someone to supply the correct formula. Note the angle in the formula is w.r.t. the lens axis. Link to post Share on other sites More sharing options...
jaapv Posted August 26, 2010 Share #35 Posted August 26, 2010 Ummm. I use the method: I take photographs. If I don't like the focussing results I take a close-up of a glass of wine before drinking it - if the wine is blurred I send the lens in. Then I drink the wine. Tastes much better than cosines. The moral being: The owner of the lens only needs to notice whether something is wrong. Even if he is mistaken he needs somebody to look at it for his peace of mind. The utmost precision is needed by the technician only. Link to post Share on other sites More sharing options...
Nicoleica Posted August 26, 2010 Share #36 Posted August 26, 2010 I use a similar method to Jaap. Except that I drink the wine before taking the photograph. If the image of the subject is more blurred than it appears to be with my eyes, then I find that a further glass of wine normally restores the balance. Link to post Share on other sites More sharing options...
bill Posted August 26, 2010 Share #37 Posted August 26, 2010 ...is this thread for real? Regards, Bill Link to post Share on other sites More sharing options...
SJP Posted August 26, 2010 Share #38 Posted August 26, 2010 ...is this thread for real? Regards, Bill sure, exept the following equation is more convenient to remember obviously: [1 - {(cos x) / (cos (x+-y)}] X 100 = [{tan(x)sin(y)+cos(y)-1}/{cos(y) + tan(x)sin(y)}] X 100 Link to post Share on other sites More sharing options...
jaapv Posted August 26, 2010 Share #39 Posted August 26, 2010 I use a similar method to Jaap. Except that I drink the wine before taking the photograph. If the image of the subject is more blurred than it appears to be with my eyes, then I find that a further glass of wine normally restores the balance. Ah yes - the double blur method. Quite valid, although I find it works best using Otard VSOP. Link to post Share on other sites More sharing options...
Guest mc_k Posted August 26, 2010 Share #40 Posted August 26, 2010 ...The utmost precision is needed by the technician only. well it all depends on what you are shooting and what you are trying to accomplish, doesn't it. Link to post Share on other sites More sharing options...
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